Hey, gang! It’s high time we had a trading game in here, and this is it. Since trading games are easy to scam for large groups, though, your movements will be more or less controlled in this one, and I’ve decided I’d go absolutely bonkers trying to play this challenge, which is usually a good sign.

What do stupid kids love? Chocolate frogs! You’ve all eaten five of them, and have collected the cards that accompany them. There are five sets of seven cards, all laid out in this spreadsheet.

In a remarkable coincidence, each of you have gotten five different-colored cards (I will be sending you links to spreadsheets with your five cards individually after this post goes up).

What’s more fun than trading at will? MANDATORY trading that’s controlled completely by a soulless random.org machine! There will be three rounds of trading, where you will be trading with two of the other six kids, which were predetermined. The mini-spreadsheet on the above spreadsheet lays out who you’ll be trading with; if you intersect with a student with the number 1, you trade in the first round. Hence, for instance, Hermione will trade with Hannah and Goyle.

You can talk to the person in question, or not. All I require of you is to say which cards you’re sending to which people. So for round one, Hermione will send me “I give Hannah (card X) and Goyle (card Y).” Once everyone has sent me their submission, I will update as soon as I can. This challenge really, REALLY doesn’t work if you non-submit, so seriously, just don’t.

At the end of the three rounds, the winner will be the person with the best poker-style hand. If you know poker, this will be easy to understand. If not, follow the list that’s also on the spreadsheet. The best possible hand is a Straight Flush, which would be five in a row of the same color. The next best would be five of the same color, but not consecutive numbers. Next is five of a kind (that is, five of the same number). Then four of a kind (same number) followed by a straight, which is five numbers in a row, but not all of the same color. Then it’s a full house (three of one number, two of another). Then three of a kind (same number). Then a pair (number) and finally the highest single card.

If you have ANY question about how this works, please ask as soon as possible.

I work tomorrow night from 2 to close. I’ll be home by the deadline at 10, however. We’re in a lull right now so I should be able to field things at that time. On Friday we’ll attempt a deadline at 7 and another at 10. If I can’t update the 7 in a timely manner, which is possible given that I’ll be at work, we’ll finish on Saturday.

The best single hand will win. Tiebreakers are many, and…sigh…I should probably mention them now. If there are multiple straight flushes, the higher card numbers win (higher cards always win within card number-specific sets). If there are two straight flushes of the same numbers, the farthest left color is given preference.

That should cover it, but it probably doesn’t. Dumbledore awaits both your idiotic and your justified questions. Cheers, Students.

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